red lion trash pump 6rlag-2lst

Solved: as it passes

Answer

The power rating of the pump is 306.5625 W.

Explanation

1. Convert the volume of water from liters to cubic meters: Given, 1 liter = 0.001 cubic meters Volume of water = 50 liters = 50 * 0.001 = 0.05 cubic meters.

2. Calculate the work done by the pump: Work done = force * distance Force = weight of water = mass * gravity Given, mass = volume * density of water = 0.05 * 1000 kg/m^3 = 50 kg Gravity, g = 9.81 m/s^2 Force = 50 * 9.81 = 490.5 N Distance = height = 15 m Work done = 490.5 * 15 = 7357.5 J

3. Calculate the power output of the pump: Power = work done / time Given time = 30 seconds Power = 7357.5 / 30 = 245.25 W

4. Consider the efficiency of the pump: Efficiency = (useful power output / input power) * 100% Given efficiency = 80% Therefore, 80% = (useful power output / input power) * 100% Useful power output = 80/100 * input power Useful power output = 0.8 * input power

5. Calculate the power rating of the pump: 0.8 * input power = 245.25 Input power = 245.25 / 0.8 = 306.5625 W

This question focuses on calculating the power rating of a pump, taking into account its efficiency. To solve this, you first need to determine the work done by the pump. Work done against gravity is calculated as the force (weight of the water) multiplied by the height it's lifted. Remember that force due to gravity is mass times the acceleration due to gravity (g, approximately 9.8 m/s²). You'll need to convert the volume of water (50 litres) to mass using its density (1 litre of water is approximately 1 kg). Once you have the work done, you can calculate the power input required to achieve this work in the given time (30 seconds). Power is defined as work done per unit time. However, the question states the pump is only 80% efficient, meaning the actual power output is 80% of the power the pump consumes. Therefore, you'll need to divide the calculated power output by the efficiency (0.80) to find the total power rating of the pump.