rubber lined slurry pump

A water pump lifts water from a level 10 m below the...

Question

A water pump lifts water from a level 10 m below the ground. Water is pumped at a rate of 30 kg/ minute with negligible velocity. Calculate the minimum horsepower the engine should have to do this.

Key Concepts

Work and Power. Work is the energy transferred when a force moves an object over a distance, and power is defined as the rate at which work is done or energy is transferred. In the context of lifting fluids, it involves calculating the work done to raise a certain mass to a certain height, and then dividing by the time taken to obtain power.

Unit Conversion. Unit conversion is important when translating calculated power into practical engine ratings. Often, calculations will provide energy or power in SI units like joules and watts, and these need to be converted into other units such as horsepower to match common engineering standards and specifications.

Gravitational Potential Energy. This concept refers to the energy an object possesses due to its position in a gravitational field. In problems involving lifting objects or fluids, this energy is calculated using the formula PE = m * g * h, where m is the mass, g is the gravitational acceleration, and h is the height lifted. It quantifies the work required to raise the object against gravity.

Mass Flow Rate. Mass flow rate is the amount of mass passing through a given surface per unit time. In engineering applications like pumping fluids, it is used to determine the overall energy and power needed to move a continuous stream of material, linking the rate of energy consumption to the rate of mass movement.

Transcript

Okay in this question of water pump lift the water from level 10 meter below the ground so h is 10 meter okay so water is pumped at the rate of 30 kg per minute so weight per minute that is m by t it is given 30 kg per minute okay so we just take an assignate second so it will be 30 divided by 60 kg per second okay or we can say 30 by 60 that is 0 .5 0 .5 kg per second it is given m by t okay so we have to find out it is with negligible velocity okay and we have to calculate the minimum horsepower the engine should have to do this okay so we know that the power p that is work done divided by time okay work done by time and work is m g h and time is t okay so this can be related as m by t multiplied by g multiplied by h okay so m by t we have 0 .5 okay multiplied by g that is 9 .8 and multiplied by h is given 10 meter okay so when we solve this will be 49 watt okay so the 49 watt pump is required to do this but the question is in horsepower okay so we know that watt divided by 746 it will be the horsepower so power in horsepower it will be 49 divided by 746 and that will be 6 .6 multiplied by 10 -d -power minus 2 horsepower...