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ACCORDING to the accepted views on atomic structure, the atoms of nickel, palladium, and platinum should, in the fundamental state, show the same outer electronic structure, namely, _s_ 2 _d_ 8, where _s_ denotes an electron with _l_=0 and _d_ an electron with _l_=2. Spectroscopic evidence seems to indicate that, in the case of palladium, the electronic distribution corresponding to the fundamental state is _d_ 10. The magnetic properties of the compounds of these elements show great dissimilarity; for example, while NiCl 2 is paramagnetic and has a magnetic moment of about 14–16 Weiss magnetons, both PdCl 2 and PtCl 2 are diamagnetic (Bose and Bhar, _Zeit. f. Physik._, Vol. 48, p. 716). This difference was explained by these authors on the assumption that in NiCl 2 the two outer _s_ electrons of the nickel atom are transferred to the two Cl atoms giving rise to a polar molecule, while in the other two compounds the two chlorine atoms are in covalent bond with the two uncoupled _d_ electrons in the atoms respectively of palladium, or of platinum, thus neutralising the magnetic moments of these atoms. It has, however, been found that both K 2 PtCl 4 and K 2 Ni(CN)4 are diamagnetic.
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