EUR
en
The work performed by the pump is equal to the weight of liquid pumped in Unit time multiplied by total Head in meters. However the pump capacity in M 3/hr and liquid specific gravity are used rather than weight of liquid pumped for work done by the pump.
The input power “P” of a pump is the mechanical power inkW or Watt taken by the shaft or coupling. So the input power of the pump also called Break Horse Power (BHP).
Pump input BHP is the power delivered to the pump shaft and is designated as brake horsepower. so pump input power also called as pump shaft power.
Pump output power is called as Water Horse Power (WHP ) or Hydraulic power and it is useful work delivered by the pump. and is usually expressed by the formula
_Hydraulic power Ph = Flow rate X Total developed head X Density X Gravitational constant_
Pump Efficiency is the ratio of pump input and output power.
i.e Efficiency of the pump is the ratio _water horse power to break horse power._
Pump Efficiency = {Pump Output / Pump Input} × 100
= {Water Horse Power / Break Horse Power} × 100
= {Hydraulic Power / Pump Shaft Power} × 100
Pump input power calculation formula or pump shaft power calculation formula
Pump Input Power = P
Q = Flow rate in m 3/sec
H = Total developed head in meters
ρ = Density in kg/m 3
g = Gravitational constant = 9.81 m/sec 2
η = Efficiency of the pump ( between 0% to 100%)
Q = Flow rate in m 3/hr
H = Total developed head in meters
ρ = Density in kg/dm 3 (1 kg/m 3 = 0.001 kg/dm 3)
η = Efficiency between 0 and <1 (not in %)
Q = Flow rate in Lt./sec ( 1 m 3/sec = 3.6 x Lt./sec)
H = Total developed head in meters
ρ= Density in kg/dm 3 (1 kg/m 3 = 0.001 kg/dm 3)
η = Efficiency of the pump ( between 0% to 100%)
Q = Flow rate in Lt./sec
H = Total developed head in meters
ρ= Density in kg/dm 3
η = Efficiency of the pump ( between 0% to 100%)
Q = Flow rate in gpm
H = Total developed head in feet
ρ= Density in lb/ft 3
η = Efficiency of the pump ( between 0% to 100%)
For an electric-motor-driven pumping unit, the overall efficiency is
_Overall efficiency = pump efficiency x motor efficiency_
The overall efficiency then becomes what is commonly called “wire-to-water” efficiency, which is expressed by the formula
The specific speed“Nq” is a parameter derived from a dimensional analysis which allows a comparison of impellers of various pump sizes even when their operating similar Q -H range. The specific speed can be used to classify the optimum impeller design.
Specific Speed of pump (Nq) is defined as the speed in RPM at which a geometrically similar impeller would run if it were reduced proportionately in size so as to delivered 75 kg of water per second to the height of 1 m.
Nq is also defined as the theoretical rotational speed at which a geometrically similar impeller would run if it were of such a size as to produce 1 m of head at a flow rate of1 m 3/sec at the best efficiency point.
The specific speed can be made a truly dimensionless characteristic parameter while retaining the same numerical value by using following equation.
N = RPM of pump
n = Rev/sec of Pump
Q = Flow rate in m 3/sec
H = Head in meters
g = Gravitational constant ( 9.81 m/sec 2)
Where N = RPM of pump
Q = Flow rate in Gallons per minute (GPM)
H = Head in feet
1. For multistage pumps the developed head (H) at best efficiency
2. Consider half total discharge in case of double suction impeller.
Radial high head impeller – up to approx. 25
Radial medium head impeller – up to approx. 40
Radial low head impeller – up to approx. 70
Mixed flow impeller – up to approx. 160
Axial flow impeller (propeller) – approx. from 140 to 400
Pump Efficiency is the most important factor while calculating power consumption. So while selection of the higher rating of pump always choose best efficiency pump set.
N = Number units power saving per year in KWH
η 2&η 1= Higher and lower overall efficiency of two pump sets.
P = Power input in kW to motor (related to low efficiency pump)
T = Running hours per year
η 2&η 1= 75% and 65% respectively
P = Power input = 40 kW
T = 3000 hours per year
N = 18461 Units (KWH)
So for same rating pump efficiency will increase by 10% then power saving will be 18461 KWH per year.
_Note : 1000 kg/m 3 = 1 kg/dm 3_
Bookmark
Daniel Féau processes personal data in order to optimise communication with our sales leads, our future clients and our established clients.
This site is protected by reCAPTCHA and the Google Privacy Policy and Terms of Service apply.